0.0064x+0.0016x^2=0.0036

Solution for 0.0064x+0.0016x^2=0.0036 equation:

0.0064x+0.0016x^2=0.0036

We move all terms to the left:

0.0064x+0.0016x^2-(0.0036)=0

We add all the numbers together, and all the variables

0.0016x^2+0.0064x-0.0036=0

a = 0.0016; b = 0.0064; c = -0.0036;
Δ = b2-4ac
Δ = 0.00642-4·0.0016·(-0.0036)
Δ = 6.4E-5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0064)-\sqrt{6.4E-5}}{2*0.0016}=\frac{-0.0064-\sqrt{6.4E-5}}{0.0032}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0064)+\sqrt{6.4E-5}}{2*0.0016}=\frac{-0.0064+\sqrt{6.4E-5}}{0.0032}
$